Identify the correct order of oxidizing power | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The oxidizing power of transition metal oxoanions depends on the reduction potential of the metal in its highest oxidation state. The standard red

Vedclass · Accepted Answer

$VO_2^+ < Cr_2O_7^{2-} < MnO_4^-$

Vedclass · Answer

(A) The oxidizing power of transition metal oxoanions depends on the reduction potential of the metal in its highest oxidation state. The standard reduction potentials $(E^\circ)$ for the given species are: $VO_2^+ + 2H^+ + e^- \rightarrow VO^{2+} + H_2O$ $(E^\circ = 1.00 \ V)$ $Cr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O$ $(E^\circ = 1.33 \ V)$ $MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$ $(E^\circ = 1.51 \ V)$ Since the oxidizing power increases with the increase in standard reduction potential,the order is $VO_2^+ < Cr_2O_7^{2-} < MnO_4^-$.

Identify the correct order of oxidizing power.

Similar Questions

Which one of the following oxides is ionic?

All $Cu(II)$ halides are known,except the iodide. The reason for this is that:

Transition elements with lower oxidation states act as........

The most acidic compound in water is

$Cu^{2+}$ ions will be reduced to $Cu^{+}$ ions by the addition of an aqueous solution of

Vedclass Test Series

Exam Paper Generator

Online Exam Module