The valence shell electronic configuration is | vedclass

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(C) Given the configuration: $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$.Substituting $n = 4$ and $x = 5$,we get the configuration of the valence and inne

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$25$

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(C) Given the configuration: $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$.Substituting $n = 4$ and $x = 5$,we get the configuration of the valence and inner shells as $3s^2 3p^6 3d^5 4s^2$.The total number of electrons is the sum of electrons in all shells: $1s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^2$.Total electrons $= 2 + 2 + 6 + 2 + 6 + 5 + 2 = 25$.Since the atom is neutral,the number of protons equals the number of electrons,which is $25$.

The valence shell electronic configuration is $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$. If $n = 4$ and $x = 5$,what is the number of protons in the element?

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