The magnetic moment of Cr in [Cr(H_2O)_6]Cl_3 | vedclass

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(D) The magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \, BM$,where $n$ is the number of unpaired electrons.Given $\mu = 3.88 \, BM$,we

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$3d_{xy}^1, 3d_{yz}^1, 3d_{xz}^1$

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(D) The magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \, BM$,where $n$ is the number of unpaired electrons.Given $\mu = 3.88 \, BM$,we have $\sqrt{n(n+2)} \approx 3.88$,which implies $n = 3$.In $[Cr(H_2O)_6]Cl_3$,the oxidation state of $Cr$ is $+3$.The electronic configuration of $Cr^{3+}$ is $[Ar] 3d^3$.Since there are $3$ unpaired electrons in the $3d$ subshell,they will occupy three different $d$-orbitals according to Hund's rule.The $d$-orbitals are $d_{xy}, d_{yz}, d_{xz}, d_{x^2-y^2},$ and $d_{z^2}$.Any combination of three distinct $d$-orbitals is possible for the $3d^3$ configuration,but $d_{xy}, d_{yz},$ and $d_{xz}$ are the standard set of $t_{2g}$ orbitals.

List-$I$	List-$II$
$A. K_2[Ni(CN)_4]$	$I. sp^3$
$B. [Ni(CO)_4]$	$II. sp^3d^2$
$C. [Co(NH_3)_6]Cl_3$	$III. dsp^2$
$D. Na_3[CoF_6]$	$IV. d^2sp^3$

The magnetic moment of $Cr$ in $[Cr(H_2O)_6]Cl_3$ is $3.88 \, BM$. Which of the following is the possible orbital distribution for $Cr$?

Similar Questions

Which of the following pairs of complex compounds are both tetrahedral and diamagnetic?

Which one of the following is an inner orbital complex as well as diamagnetic in behaviour? (Atomic number: $Zn = 30$,$Cr = 24$,$Co = 27$,$Ni = 28$)

Match List-$I$ with List-$II$:

List-$I$ List-$II$

$A. K_2[Ni(CN)_4]$ $I. sp^3$

$B. [Ni(CO)_4]$ $II. sp^3d^2$

$C. [Co(NH_3)_6]Cl_3$ $III. dsp^2$

$D. Na_3[CoF_6]$ $IV. d^2sp^3$

Choose the correct answer from the options given below:

Which of the following statements is $NOT$ correct regarding the complex $[Co(NH_3)_6]^{3+}$?

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