(i) La(OH)_3 is the least basic among lanthan | vedclass

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(B) Statement $(i)$ is incorrect because $La(OH)_3$ is the most basic lanthanide hydroxide due to the largest ionic radius of $La^{3+}$. As we move fr

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$(ii)$ and $(iii)$

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(B) Statement $(i)$ is incorrect because $La(OH)_3$ is the most basic lanthanide hydroxide due to the largest ionic radius of $La^{3+}$. As we move from $La$ to $Lu$,the ionic radius decreases,leading to a decrease in basicity.Statement $(ii)$ is correct because $Zr^{4+}$ and $Hf^{4+}$ have almost identical ionic radii due to lanthanoid contraction.Statement $(iii)$ is correct because $Ce^{4+}$ has a strong tendency to gain an electron to form the stable $Ce^{3+}$ $(4f^1)$ configuration,thus acting as a strong oxidizing agent.Therefore,statements $(ii)$ and $(iii)$ are correct.

$(i) La(OH)_3$ is the least basic among lanthanide hydroxides. $(ii) Zr^{4+}$ and $Hf^{4+}$ have almost identical ionic radii. $(iii) Ce^{4+}$ can act as an oxidizing agent. Which of the above statements are correct?

Similar Questions

Which of the following elements have half-filled $f$-orbitals in their ground state?
(Given: atomic number $Sm = 62$; $Eu = 63$; $Tb = 65$; $Gd = 64$; $Pm = 61$)
$A.$ $Sm$ $B.$ $Eu$ $C.$ $Tb$ $D.$ $Gd$ $E.$ $Pm$
Choose the correct answer from the options given below:

In lanthanides,with an increase in atomic number,the atomic radius decreases,except for the element $\underline{X}$. What is $\underline{X}$?

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Write a note on oxidation states shown by lanthanoids.

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