The main reason for the actinoids exhibiting a larger number of oxidation states than the lanthanoids is:

  • A
    $4f$-orbitals are more extended than $5f$-orbitals.
  • B
    The energy difference between $5f$ and $6d$ orbitals is less than that between $4f$ and $5d$ orbitals.
  • C
    The energy difference between $5f$ and $6d$ orbitals is more than that between $4f$ and $5d$ orbitals.
  • D
    Actinoids are more reactive in nature than lanthanoids.

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Similar Questions

Match the properties given in List-$I$ with the elements given in List-$II$:
List-$I$ (Property) List-$II$ (Element)
$(A)$ Lanthanoid showing $+4$ oxidation state $(i)$ $Pm$
$(B)$ Lanthanoid showing $+2$ oxidation state $(ii)$ $Ce$
$(C)$ Radioactive lanthanoid $(iii)$ $Lu$
$(D)$ Lanthanoid with $4f^7$ configuration in $+3$ state $(iv)$ $Eu$
$(E)$ Lanthanoid with $4f^{14}$ configuration in $+3$ state $(v)$ $Gd$
- $(vi)$ $Dy$

Which electronic configuration is common to all actinoid elements?

The lanthanoid that does $NOT$ show $+4$ oxidation state is

Larger number of oxidation states are exhibited by the actinoids than those by the lanthanoids,the main reason being

Which elements exhibit nearly identical properties?

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