Which of the following electronic configurati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The maximum oxidation state of a transition element is determined by the total number of electrons in the $(n-1)d$ and $ns$ orbitals.For option $A

Vedclass · Accepted Answer

$(n - 1)d^8 ns^2$

Vedclass · Answer

(B) The maximum oxidation state of a transition element is determined by the total number of electrons in the $(n-1)d$ and $ns$ orbitals.For option $A$: $(n-1)d^5 ns^2$,total electrons = $5 + 2 = 7$.For option $B$: $(n-1)d^8 ns^2$,total electrons = $8 + 2 = 10$.For option $C$: $(n-1)d^5 ns^1$,total electrons = $5 + 1 = 6$.For option $D$: $(n-1)d^3 ns^2$,total electrons = $3 + 2 = 5$.Since the configuration in option $B$ has the highest number of valence electrons available for bonding,it can exhibit the highest oxidation state.

Which of the following electronic configurations represents an atom that can exhibit the highest oxidation state?

Similar Questions

Which one of the following does not correctly represent the correct order of the property indicated against it?

$La$ (lanthanum) having atomic number $57$ is a member of

The correct order of ionisation energy is:

The correct electronic configuration of the element $Au$ is

In which of the following ions is $d-d$ transition $NOT$ possible?

Vedclass Test Series

Exam Paper Generator

Online Exam Module