The common oxidation state of the elements of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The lanthanoids are a series of $14$ elements from Cerium ($Ce$,$Z=58$) to Lutetium ($Lu$,$Z=71$).All lanthanoids exhibit a common oxidation state

Vedclass · Accepted Answer

$+3$

Vedclass · Answer

(B) The lanthanoids are a series of $14$ elements from Cerium ($Ce$,$Z=58$) to Lutetium ($Lu$,$Z=71$).All lanthanoids exhibit a common oxidation state of $+3$ due to the loss of two $6s$ electrons and one $4f$ or $5d$ electron.While some elements show $+2$ or $+4$ oxidation states in specific compounds,$+3$ is the most stable and characteristic oxidation state for the entire series.

The common oxidation state of the elements of the lanthanoid series is .....

Similar Questions

What is the highest oxidation state exhibited by actinoids?

Use Hund's rule to derive the electronic configuration of $Ce^{3+}$ ion and calculate its magnetic moment on the basis of 'spin-only' formula.

Which of the following elements are included in the actinoid series?

Europium is

What is the effect of lanthanoid contraction in the lanthanoid series of elements with increasing atomic number?

Vedclass Test Series

Exam Paper Generator

Online Exam Module