C_2H_5I xrightarrow{text{alc. } KOH} X xright | vedclass

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Question

(B) $1$. $C_2H_5I$ reacts with alcoholic $KOH$ (dehydrohalogenation) to form ethene $(X)$: $C_2H_5I \xrightarrow{	ext{alc. } KOH} CH_2=CH_2 (X)$.$2$.

Vedclass · Accepted Answer

$NC-CH_2-CH_2-CN$

Vedclass · Answer

(B) $1$. $C_2H_5I$ reacts with alcoholic $KOH$ (dehydrohalogenation) to form ethene $(X)$: $C_2H_5I \xrightarrow{	ext{alc. } KOH} CH_2=CH_2 (X)$.$2$. Ethene reacts with $Br_2$ (electrophilic addition) to form $1,2$-dibromoethane $(Y)$: $CH_2=CH_2 \xrightarrow{Br_2} CH_2Br-CH_2Br (Y)$.$3$. $1,2$-dibromoethane reacts with $KCN$ (nucleophilic substitution) to form succinonitrile $(Z)$: $CH_2Br-CH_2Br \xrightarrow{KCN} CN-CH_2-CH_2-CN (Z)$.

$C_2H_5I$ $\xrightarrow{\text{alc. } KOH} X$ $\xrightarrow{Br_2} Y$ $\xrightarrow{KCN} Z$; $Z = \dots$

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