When toluene is reacted with $Br_2/Fe$,$p$-bromotoluene is formed as the major product because the $CH_3$ group is...
- Aortho and para directing
- Bmeta directing
- Cdeactivates the ring by hyperconjugation
- Ddeactivates the ring
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The major product formed in the following reaction sequence is:
$C_6H_5-CHBr-CH_2Br$ $\xrightarrow[(ii) NaNH_2]{(i) alc. KOH}$ $\xrightarrow[(iii) \text{Red hot iron tube}, 873 K]{}$
$C_6H_5-CHBr-CH_2Br$ $\xrightarrow[(ii) NaNH_2]{(i) alc. KOH}$ $\xrightarrow[(iii) \text{Red hot iron tube}, 873 K]{}$
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