The molecular formula of compound A is C_2Cl_ | vedclass

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(A) The molecular formula $C_2Cl_3OH$ corresponds to $CCl_3CHO$ (Chloral).Chloral contains an aldehyde group $(-CHO)$,which allows it to reduce Fehlin

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Chloral

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(A) The molecular formula $C_2Cl_3OH$ corresponds to $CCl_3CHO$ (Chloral).Chloral contains an aldehyde group $(-CHO)$,which allows it to reduce Fehling's solution.Upon oxidation,chloral $(CCl_3CHO)$ is converted into trichloroacetic acid $(CCl_3COOH)$,which is a monocarboxylic acid.Ethyl alcohol reacts with chlorine to form acetaldehyde,which further reacts with chlorine to produce chloral:$CH_3CH_2OH + Cl_2 	o CH_3CHO + 2HCl$$CH_3CHO + 3Cl_2 	o CCl_3CHO + 3HCl$Therefore,compound $A$ is Chloral.

The molecular formula of compound $A$ is $C_2Cl_3OH$. It reduces Fehling's solution and on oxidation gives a monocarboxylic acid $B$. Compound $A$ is obtained by the reaction of chlorine with ethyl alcohol. What is $A$?

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