Given A = text{Nylon-}6,6,B = text{Buna-}S,an | vedclass

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(B) The strength of intermolecular forces in polymers depends on their structure:$1$. $B = 	ext{Buna-}S$ is an elastomer,which has the weakest interm

Vedclass · Accepted Answer

$B < C < A$

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(B) The strength of intermolecular forces in polymers depends on their structure:$1$. $B = 	ext{Buna-}S$ is an elastomer,which has the weakest intermolecular forces (weak van der Waals forces).$2$. $C = 	ext{Polythene}$ is a thermoplastic,which has intermediate intermolecular forces (stronger van der Waals forces than elastomers).$3$. $A = 	ext{Nylon-}6,6$ is a fiber,which has the strongest intermolecular forces due to hydrogen bonding.Therefore,the increasing order of intermolecular forces is $B < C < A$.

List-$I$	List-$II$
$A$. Natural rubber	$i$. $\beta$-glucose
$B$. Cellulose	$ii$. Isoprene
$C$. Nylon-$6$	$iii$. Tetrafluoroethylene
$D$. Teflon	$iv$. Caprolactam

Given $A = \text{Nylon-}6,6$,$B = \text{Buna-}S$,and $C = \text{Polythene}$. Arrange these polymers in the increasing order of their intermolecular forces (from weakest to strongest).

Similar Questions

Match the following items in List-$I$ with their corresponding monomer units in List-$II$.
List-$I$ List-$II$
$A$. Natural rubber $i$. $\beta$-glucose
$B$. Cellulose $ii$. Isoprene
$C$. Nylon-$6$ $iii$. Tetrafluoroethylene
$D$. Teflon $iv$. Caprolactam

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