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(D) The electrolysis of a mixture of sodium ethanoate $(CH_3COONa)$ and sodium propanoate $(CH_3CH_2COONa)$ follows the Kolbe's electrolysis mechanism

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All of the above

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(D) The electrolysis of a mixture of sodium ethanoate $(CH_3COONa)$ and sodium propanoate $(CH_3CH_2COONa)$ follows the Kolbe's electrolysis mechanism. During this process,two types of alkyl radicals are formed: methyl radical $(CH_3^{\bullet})$ and ethyl radical $(CH_3CH_2^{\bullet})$. These radicals combine in all possible ways to form alkanes: $1$. Combination of two methyl radicals: $CH_3^{\bullet} + CH_3^{\bullet} \rightarrow CH_3CH_3$ (Ethane) $2$. Combination of two ethyl radicals: $CH_3CH_2^{\bullet} + CH_3CH_2^{\bullet} \rightarrow CH_3CH_2CH_2CH_3$ (Butane) $3$. Combination of one methyl and one ethyl radical: $CH_3^{\bullet} + CH_3CH_2^{\bullet} \rightarrow CH_3CH_2CH_3$ (Propane) Therefore,all three products are obtained.

Which products are obtained from the electrolysis of an aqueous mixture of sodium ethanoate and sodium propanoate?

Similar Questions

In the following sequence of reactions,the $P$ is:

Given below are two statements :
Statement-$I$ : $2-$methylbutane on oxidation with $KMnO_4$ gives $2-$methylbutan$-2-$ol.
Statement-$II$ : $n-$alkanes can be easily oxidised to corresponding alcohol with $KMnO_4$.
Choose the correct option:

Which hydrocarbon will be most stable?

The major products $P$ and $Q$ of the following reactions respectively are:
$I$. $n$-pentyl bromide $\xrightarrow{Zn / H^{+}} P$
$II$. $n$-pentyl bromide $\xrightarrow[\text{Dry ether}]{Na} Q$

In the preparation of alkanes,a concentrated aqueous solution of sodium or potassium salts of saturated carboxylic acids is subjected to:

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