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(C) The debromination of vicinal dihalides using zinc dust $(Zn)$ in an alcoholic solvent follows an $E2$ elimination mechanism. For meso-$2,3$-dibrom

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trans-$2$-butene

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(C) The debromination of vicinal dihalides using zinc dust $(Zn)$ in an alcoholic solvent follows an $E2$ elimination mechanism. For meso-$2,3$-dibromobutane,the molecule can adopt a conformation where the two bromine atoms are anti-periplanar to each other. Upon elimination of $ZnBr_2$,the anti-elimination process leads to the formation of trans-$2$-butene as the major product because the methyl groups are positioned opposite to each other in the transition state.

What is the major product obtained from the debromination of meso-$2,3$-dibromobutane?

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