Which reagent can be used to distinguish betw | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$-butyne $(CH_3-CH_2-C \equiv CH)$ is a terminal alkyne containing an acidic hydrogen atom attached to the $sp$-hybridized carbon.Terminal alkyn

Vedclass · Accepted Answer

Ammoniacal $Cu_2Cl_2$ solution

Vedclass · Answer

(D) $1$-butyne $(CH_3-CH_2-C \equiv CH)$ is a terminal alkyne containing an acidic hydrogen atom attached to the $sp$-hybridized carbon.Terminal alkynes react with ammoniacal cuprous chloride $(Cu_2Cl_2)$ to form a red precipitate of copper$(I)$ acetylide.$2$-butyne $(CH_3-C \equiv C-CH_3)$ is a non-terminal alkyne and does not have an acidic hydrogen atom.Therefore,it does not react with ammoniacal $Cu_2Cl_2$ solution.Thus,ammoniacal $Cu_2Cl_2$ is used to distinguish between them.

Which reagent can be used to distinguish between $1$-butyne and $2$-butyne?

Similar Questions

Addition of $HCN$ to ethyne in the presence of $Ba(CN)_2$ as a catalyst gives:

$CH_3 - C \equiv C - CH_3 \xrightarrow[CH_3COOH]{BH_3, THF} \text{Major product}$

$CH \equiv CH$ $\xrightarrow[H_2SO_4]{H_2O/Hg^{2+}} X$ $\xrightarrow{LiAlH_4} Y$ $\xrightarrow{P_4/Br_2} Z$. Here $Z$ is

Ozonolysis of acetylene $(HC \equiv CH)$ gives:

To carry out the above conversion,$(A)$ and $(B)$ respectively are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module