(A) In the nitration of benzene,the reaction between nitric acid and sulfuric acid is as follows: $HO-NO_2 + H-OSO_3H \rightarrow NO_2^+ + H_2O + HSO_

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(A) In the nitration of benzene,the reaction between nitric acid and sulfuric acid is as follows: $HO-NO_2 + H-OSO_3H \rightarrow NO_2^+ + H_2O + HSO_4^-$ Here,$H_2SO_4$ is a stronger acid than $HNO_3$,so it donates a proton $(H^+)$ to $HNO_3$. Since $HNO_3$ accepts a proton,it acts as a $Base$ in this reaction.