2-Butene exhibits geometrical isomerism due t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Geometrical isomerism in alkenes like $2$-butene $(CH_3-CH=CH-CH_3)$ arises because the carbon-carbon double bond consists of a $\sigma$-bond and

Vedclass · Accepted Answer

Restricted rotation around the double bond

Vedclass · Answer

(A) Geometrical isomerism in alkenes like $2$-butene $(CH_3-CH=CH-CH_3)$ arises because the carbon-carbon double bond consists of a $\sigma$-bond and a $\pi$-bond. The presence of the $\pi$-bond prevents free rotation around the $C=C$ axis,resulting in restricted rotation. This restricted rotation allows for the existence of distinct spatial arrangements of atoms or groups attached to the double-bonded carbons,leading to $cis$ and $trans$ isomers.

$2$-Butene exhibits geometrical isomerism due to:

Similar Questions

The total number of stereoisomers of the compound $1$-bromo-$3$-chlorocyclobutane is:

The prefixes $syn$ and $anti$ are used to denote $.....$.

Which one of the following compounds can exist as $cis-trans$ isomers?

Which of the following can show geometrical isomerism?

$CH_2 = CH - CH = CH - CH = CH_2$
How many geometrical isomers are possible for this compound?

Vedclass Test Series

Exam Paper Generator

Online Exam Module