What is the product A in the given reaction?C | vedclass

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(C) The reaction of an alkyne with $H^+ / Hg^{2+}$ is an acid-catalyzed hydration reaction,which follows Markovnikov's rule.For the alkyne $C_6H_5-C \

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$C_6H_5-CO-CH_2-CH_3$

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(C) The reaction of an alkyne with $H^+ / Hg^{2+}$ is an acid-catalyzed hydration reaction,which follows Markovnikov's rule.For the alkyne $C_6H_5-C \equiv C-CH_3$,the addition of water occurs across the triple bond.The $OH^-$ group attaches to the carbon atom that is more substituted or stabilized by the phenyl group,leading to the formation of an enol intermediate.Specifically,the intermediate is $C_6H_5-C(OH)=CH-CH_3$.This enol then undergoes tautomerization to form the more stable ketone,which is $C_6H_5-CO-CH_2-CH_3$ (propiophenone derivative).However,looking at the options provided,option $C$ represents the final ketone product.

What is the product $A$ in the given reaction?
$C_6H_5-C \equiv C-CH_3 \xrightarrow{H^+ / Hg^{2+}} A$

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What is the product $A$ in the given reaction?$C_6H_5-C \equiv C-CH_3 \xrightarrow{H^+ / Hg^{2+}} A$