In the Friedel-Crafts reaction,toluene can be | vedclass

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Question

(A) The Friedel-Crafts alkylation of benzene involves the reaction of benzene $(C_6H_6)$ with an alkyl halide (such as $CH_3Cl$) in the presence of an

Vedclass · Accepted Answer

$C_6H_6 + CH_3Cl$

Vedclass · Answer

(A) The Friedel-Crafts alkylation of benzene involves the reaction of benzene $(C_6H_6)$ with an alkyl halide (such as $CH_3Cl$) in the presence of an anhydrous Lewis acid catalyst like $AlCl_3$.This reaction substitutes a hydrogen atom on the benzene ring with an alkyl group.For the preparation of toluene $(C_6H_5CH_3)$,benzene reacts with methyl chloride $(CH_3Cl)$:$C_6H_6 + CH_3Cl \xrightarrow{Anhydrous \ AlCl_3} C_6H_5CH_3 + HCl$Therefore,the correct option is $A$.

In the Friedel-Crafts reaction,toluene can be prepared by using:

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