When alcoholic KOH is reacted with CH_3CH_2Cl | vedclass

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Question

(A) In the presence of alcoholic $KOH$,the $KOH$ reacts with the ethanol solvent to produce ethoxide ions $(C_2H_5O^{-})$.$KOH + C_2H_5OH \rightarrow

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$C_2H_5O^{-}$

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(A) In the presence of alcoholic $KOH$,the $KOH$ reacts with the ethanol solvent to produce ethoxide ions $(C_2H_5O^{-})$.$KOH + C_2H_5OH \rightarrow C_2H_5O^{-} + K^{+} + H_2O$.Since the ethoxide ion $(C_2H_5O^{-})$ is a much stronger base than the hydroxide ion $(OH^{-})$,it acts as the primary attacking reagent in the dehydrohalogenation (elimination) reaction of $CH_3CH_2Cl$ to form ethene $(CH_2=CH_2)$.

Reaction	Product
$I$. $RX + AgCN$	$RNC$
$II$. $RX + KCN$	$RCN$
$III$. $RX + KNO_2$	$RONO$
$IV$. $RX + AgNO_2$	$RNO_2$

When alcoholic $KOH$ is reacted with $CH_3CH_2Cl$ to form an alkene,which species acts as the attacking reagent?

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$CH_3-CH_2-CH(Br)-CH_3 \xrightarrow{Alc. KOH} X$ (major)
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Product $(X)$ and $(Y)$ respectively are:

Which of the following pairs is/are correctly matched?

Reaction Product

$I$. $RX + AgCN$ $RNC$

$II$. $RX + KCN$ $RCN$

$III$. $RX + KNO_2$ $RONO$

$IV$. $RX + AgNO_2$ $RNO_2$

The product obtained by the reaction of propene with $ICl$ is .............

The $S_N2$ product of the following reaction is:

The product obtained on reaction of $C_2H_5Cl$ with hydrogen over palladium carbon is

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