What is the product obtained when the compoun | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of an alkene with $NaIO_4$ in the presence of a catalytic amount of $KMnO_4$ is a method of oxidative cleavage of the double bond.For

Vedclass · Accepted Answer

$CH_3COCH_3 + CH_3CHO$

Vedclass · Answer

(D) The reaction of an alkene with $NaIO_4$ in the presence of a catalytic amount of $KMnO_4$ is a method of oxidative cleavage of the double bond.For the given compound $CH_3-C(CH_3)=CH-CH_3$ ($2$-methylbut$-2-$ene):$1$. The double bond breaks between the $C_2$ and $C_3$ carbons.$2$. The $C_2$ carbon is bonded to two methyl groups,forming acetone $(CH_3COCH_3)$.$3$. The $C_3$ carbon is bonded to one hydrogen and one methyl group,forming acetaldehyde $(CH_3CHO)$.Thus,the reaction is: $CH_3-C(CH_3)=CH-CH_3 \xrightarrow{NaIO_4/KMnO_4} CH_3COCH_3 + CH_3CHO$.

What is the product obtained when the compound $CH_3-C(CH_3)=CH-CH_3$ reacts in the presence of $NaIO_4/KMnO_4$?

Similar Questions

Dalda is prepared from oils by

In the following reaction,$P$ gives two products $Q$ and $R$ each in $40 \,\%$ yield. If the reaction is carried out with $420 \,mg$ of $P$,the reaction yields $108.8 \,mg$ of $Q$. The amount of $R$ produced in the reaction is closest to $....\, mg$.

Ethylene reacts with bromine to form

$CH_3 - CH = CH_2 \xrightarrow[(2) CH_3CO_2T]{(1) THF : BD_3} (A)$; Product $(A)$ of the above reaction is

What is the product obtained when the compound $CH_3-C(CH_3)=CH-CH_3$ is treated with $KMnO_4$ in the presence of $NaIO_4$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module