What is the correct order of bond dissociatio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The bond dissociation energy $(BDE)$ is inversely proportional to the stability of the free radical formed after the homolytic cleavage of the $C-

Vedclass · Accepted Answer

$IV > I > II > III$

Vedclass · Answer

(A) The bond dissociation energy $(BDE)$ is inversely proportional to the stability of the free radical formed after the homolytic cleavage of the $C-H$ bond.$I. \, CH_3-H \rightarrow \cdot CH_3$ (Methyl radical,least stable)$II. \, CH_3CH_2-H \rightarrow CH_3\cdot CH_2$ (Primary radical,more stable than methyl)$III. \, CH_2=CH-CH_2-H \rightarrow CH_2=CH-\cdot CH_2$ (Allyl radical,resonance stabilized,very stable)$IV. \, C_6H_5-H \rightarrow \cdot C_6H_5$ (Phenyl radical,$sp^2$ hybridized carbon,least stable due to high $s$-character)Comparing the stability of radicals: $Allyl > Ethyl > Methyl > Phenyl$.Therefore,the order of $BDE$ is: $Phenyl > Methyl > Ethyl > Allyl$.Thus,the correct order is $IV > I > II > III$.

What is the correct order of bond dissociation energy for the following $C-H$ bonds?
$I. \, CH_3-H$
$II. \, CH_3CH_2-H$
$III. \, CH_2=CH-CH_2-H$
$IV. \, C_6H_5-H$

Similar Questions

The conversion of cyclohexene to $HO-(CH_2)_6-OH$ can be achieved by:

Which one of the following alkenes will react fastest with $H_2$ under catalytic hydrogenation condition?

Consider the following reactions:
$(a)$ $CH_3-CH=CH_2 + HBr \rightarrow CH_3-CH(Br)-CH_3$
$(b)$ $CH_3-CH=CH_2 + HBr \xrightarrow{Peroxide} CH_3-CH_2-CH_2Br$
$(c)$ $CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$
Which of these reactions proceed via a free radical mechanism?

The enolic form of acetone contains

Structure of $A$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What is the correct order of bond dissociation energy for the following $C-H$ bonds?$I. \, CH_3-H$$II. \, CH_3CH_2-H$$III. \, CH_2=CH-CH_2-H$$IV. \, C_6H_5-H$