Consider the following reaction: CH_2 = CH_2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of ethene with dilute alkaline $KMnO_4$ (Baeyer's reagent) is a syn-hydroxylation reaction.In this mechanism,the two oxygen atoms add

Vedclass · Accepted Answer

Both are obtained from $H_2O$.

Vedclass · Answer

(B) The reaction of ethene with dilute alkaline $KMnO_4$ (Baeyer's reagent) is a syn-hydroxylation reaction.In this mechanism,the two oxygen atoms added to the double bond are derived from the permanganate ion $(MnO_4^-)$.Therefore,the statement that both oxygen atoms are obtained from $KMnO_4$ is correct.Statements $B$,$C$,and $D$ are incorrect as they suggest the oxygen atoms come from $H_2O$ or $NaOH$.

Consider the following reaction: $CH_2 = CH_2 \xrightarrow[H_2O, NaOH]{dilute \ KMnO_4} HOCH_2 - CH_2OH$. Which statement is incorrect regarding the two oxygen atoms obtained in the product?

Similar Questions

Which method can be used to prepare $Propane$ from $Propene$?

Unsaturation in organic compounds is detected by ...........

In which of the following,addition of $HBr$ does not take place against Markownikoff's rule,or for which is the Anti-Markownikoff addition of $HBr$ not observed?

Why is $CCl_{4}$ added in the bromination of an alkene?

The product $(A)$ formed in the following reaction sequence is :
$CH_3-C \equiv CH$ $\rightarrow[(ii) HCN]{(i) Hg^{2+}, H_2SO_4}$ $\xrightarrow[(iii) H_2 / Ni]{} (A)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module