In the reaction sequence $CaC_2$ $\xrightarrow{H_2O} A$ $\xrightarrow[dil. H_2SO_4]{Hg^{+2}} B$ $\xrightarrow{Ni} H_2 C$,the product $C$ is:
- A$CH_3OH$
- B$CH_3CHO$
- C$C_2H_5OH$
- D$C_2H_4$
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Similar Questions
In the reaction
$R - C \equiv C - R \xrightarrow{Pd + CaCO_3} B$
$R - C \equiv C - R \xrightarrow{Na + liq. NH_3} A$
$A$ and $B$ are geometrical isomers. Then:
$R - C \equiv C - R \xrightarrow{Pd + CaCO_3} B$
$R - C \equiv C - R \xrightarrow{Na + liq. NH_3} A$
$A$ and $B$ are geometrical isomers. Then:
Difficult
View Solution$CaC_2$ reacts with $H_2O$ to produce ...... .
Easy
View Solution$Be_2C + H_2O \rightarrow Be(OH)_2 + X$
$CaC_2 + H_2O \rightarrow Ca(OH)_2 + Y$
Then $X$ and $Y$ are respectively:
$CaC_2 + H_2O \rightarrow Ca(OH)_2 + Y$
Then $X$ and $Y$ are respectively:
Medium
View SolutionWhich of the following is Lindlar catalyst?
$CH \equiv CH + CO + H_2O \xrightarrow{Ni(CO)_4} \text{Product}$. For this reaction,which statement is false?
Medium
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