What is the product of the reaction: CH_3-CH= | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of $NOCl$ (Tilden's reagent) with an alkene follows Markovnikov's rule. $NOCl$ dissociates into $NO^+$ (electrophile) and $Cl^-$ (nuc

Vedclass · Accepted Answer

$CH_3-CH(Cl)-CH_2(NO)$

Vedclass · Answer

(A) The reaction of $NOCl$ (Tilden's reagent) with an alkene follows Markovnikov's rule. $NOCl$ dissociates into $NO^+$ (electrophile) and $Cl^-$ (nucleophile). In propene $(CH_3-CH=CH_2)$,the electrophilic addition of $NO^+$ occurs at the terminal carbon $(CH_2)$ to form a more stable secondary carbocation $(CH_3-CH^+-CH_2-NO)$. Subsequently,the nucleophile $Cl^-$ attacks the carbocation to form $CH_3-CH(Cl)-CH_2(NO)$.

What is the product of the reaction: $CH_3-CH=CH_2 \xrightarrow{NOCl}$?

Similar Questions

The major product of the following reaction is

Product $(A)$ will be

$A$ dibromide $X$ $(C_4H_8Br_2)$ on dehydrohalogenation gave $Y$,which on reduction with $Z$ gave a non-polar isomer of $C_4H_8$. What are $X$ and $Z$ respectively?

What will be the product $B$ formed in the following reaction sequence?
$CH_3CH_2CH_2OH$ $\xrightarrow{PCl_5} A$ $\xrightarrow{alc. KOH} B$

What will be the product of the reaction: $CH_3-CH=C(CH_3)_2 + HCl \to$ ?

Vedclass Test Series

Exam Paper Generator

Online Exam Module