The correct order of the electron-donating or withdrawing effect (inductive/mesomeric effect) for the groups $-NH_2, -OCH_3, -C_6H_5$,and $-NO_2$ is:

  • A
    $-NH_2 > -OCH_3 > -C_6H_5 > -NO_2$
  • B
    $-NO_2 > -C_6H_5 > -OCH_3 > -NH_2$
  • C
    $-OCH_3 > -NH_2 > -C_6H_5 > -NO_2$
  • D
    $-OCH_3 > -NO_2 > -NH_2 > -C_6H_5$

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Arrange the following according to the instructions:
$(i)$ Arrange in descending order of acidic strength:
$CH_3COOH, (CH_3)_3CCOOH, (CH_3)_2CHCOOH, CH_3CH_2COOH$
(ii) Arrange in descending order of stability:
$\stackrel{+}{CH}_3, (CH_3)_3\stackrel{+}{C}, CH_3CH_2^+, (CH_3)_2\stackrel{+}{CH}$
(iii) Arrange in increasing order of acidic strength:
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(iv) Arrange in increasing order of stability:
$(a)$ $CH_3CH=CH-CHO$
$(b)$ $CH_3\stackrel{+}{CH}-CH=C-O:^-$
$(c)$ $\stackrel{+}{CH}_2-CH=CH-C=O$
$(v)$ Arrange in decreasing order of stability:
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