What is the decreasing order of acidic streng | vedclass

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(C) The acidity of hydrocarbons depends on the percentage of $s$-character in the $C-H$ bond.$1$. Ethyne $(CH \equiv CH)$ has $sp$ hybridization ($50\

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$III > IV > II > I$

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(C) The acidity of hydrocarbons depends on the percentage of $s$-character in the $C-H$ bond.$1$. Ethyne $(CH \equiv CH)$ has $sp$ hybridization ($50\% \ s$-character).$2$. Propyne $(CH_3-C \equiv CH)$ has an acidic terminal hydrogen attached to an $sp$ hybridized carbon.$3$. Ethene $(CH_2=CH_2)$ has $sp^2$ hybridization ($33.3\% \ s$-character).$4$. Ethane $(CH_3-CH_3)$ has $sp^3$ hybridization ($25\% \ s$-character).Comparing ethyne $(III)$ and propyne $(IV)$,the methyl group in propyne is electron-donating ($+I$ effect),which decreases the acidity of the terminal hydrogen compared to ethyne.Thus,the decreasing order of acidity is: $III > IV > II > I$.

What is the decreasing order of acidic strength for ethane $(I)$,ethene $(II)$,ethyne $(III)$,and propyne $(IV)$?

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