What is the major product formed when 2-methy | vedclass

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(A) The reaction of alkanes with bromine in the presence of sunlight (or $UV$ light) is a free radical substitution reaction. Bromination is highly se

Vedclass · Accepted Answer

$2$-bromo-$2$-methylbutane

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(A) The reaction of alkanes with bromine in the presence of sunlight (or $UV$ light) is a free radical substitution reaction. Bromination is highly selective compared to chlorination. The reactivity order of $C-H$ bonds towards free radical substitution is $3^\circ > 2^\circ > 1^\circ$. In $2$-methylbutane $(CH_3-CH(CH_3)-CH_2-CH_3)$,the $3^\circ$ hydrogen atom is present at the $C-2$ position. Therefore,the bromine radical will abstract the $3^\circ$ hydrogen to form the most stable tertiary free radical,which then reacts with $Br_2$ to form $2$-bromo-$2$-methylbutane as the major product.

What is the major product formed when $2$-methylbutane reacts with bromine in the presence of sunlight?

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