A hydrocarbon does not decolorize alkaline KM | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. Alkaline $KMnO_4$ (Baeyer's reagent) is used to test for unsaturation (alkenes and alkynes). It gets decolorized by compounds containing doub

Vedclass · Accepted Answer

Benzene

Vedclass · Answer

(A) $1$. Alkaline $KMnO_4$ (Baeyer's reagent) is used to test for unsaturation (alkenes and alkynes). It gets decolorized by compounds containing double or triple bonds.$2$. Ammoniacal silver nitrate (Tollens' reagent) reacts with terminal alkynes (alkynes with a hydrogen atom on the triple-bonded carbon) to form a white precipitate of silver acetylide.$3$. Benzene $(C_6H_6)$ is an aromatic hydrocarbon. It is stable and does not react with Baeyer's reagent under normal conditions,nor does it have acidic terminal hydrogen to react with Tollens' reagent.$4$. Acetylene $(C_2H_2)$,Propyne $(CH_3C\equiv CH)$,and But$-1-$yne $(CH_3CH_2C\equiv CH)$ are all terminal alkynes; they would decolorize $KMnO_4$ and react with ammoniacal silver nitrate.$5$. Therefore,the correct answer is Benzene.

$A$ hydrocarbon does not decolorize alkaline $KMnO_4$ solution and does not give a precipitate with ammoniacal silver nitrate. This hydrocarbon is .......

Similar Questions

Which type of chemical reactions are given by arene compounds? Give their suitable examples and reactions.

The reaction shown below proceeds through which mechanism?

Designate whether each of the following compounds is aromatic or not aromatic.

Benzene is prepared in the laboratory from which one of the following compounds?

Calculate the sum of $\alpha$-hydrogen atoms in the given structures $(i)$ and $(ii)$:
$(i)$ $1,3$-dimethylbenzene
(ii) $1,3$-diethylbenzene
Sum $= (i) + (ii) = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module