Chlorination of substance A gives substance B | vedclass

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(A) $1$. Substance $C$ decolorizes Baeyer's reagent,which indicates that $C$ is an alkene.$2$. Ozonolysis of $C$ gives $HCHO$ (formaldehyde),which mea

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$C_2H_6$

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(A) $1$. Substance $C$ decolorizes Baeyer's reagent,which indicates that $C$ is an alkene.$2$. Ozonolysis of $C$ gives $HCHO$ (formaldehyde),which means $C$ must contain a terminal methylene group $(CH_2=)$.$3$. Since $C$ is formed from $B$ by dehydrohalogenation (using alcoholic $KOH$),$B$ must be an alkyl halide.$4$. If $C$ is ethene $(CH_2=CH_2)$,then $B$ is ethyl chloride $(CH_3CH_2Cl)$,and $A$ is ethane $(C_2H_6)$.$5$. Reaction sequence: $C_2H_6$ $\xrightarrow{Cl_2/h
u} C_2H_5Cl (B)$ $\xrightarrow{alc. KOH} CH_2=CH_2 (C)$ $\xrightarrow{O_3/Zn, H_2O} 2HCHO$.

List-$I$ Name reaction	List-$II$ Product obtainable
$A.$ Swarts reaction	$I.$ Ethyl benzene
$B.$ Sandmeyer's reaction	$II.$ Ethyl iodide
$C.$ Wurtz Fittig reaction	$III.$ Cyanobenzene
$D.$ Finkelstein reaction	$IV.$ Ethyl fluoride

Chlorination of substance $A$ gives substance $B$. Substance $B$ reacts with alcoholic $KOH$ to give substance $C$,which decolorizes Baeyer's reagent. Ozonolysis of substance $C$ gives $HCHO$. What is substance $A$?

Similar Questions

Complete the following reactions:
$(1)$ $1$-Chloropropane $\xrightarrow[{KOH}]{{\text{ethanol}}} (B)$ $\xrightarrow[{CCl_4}]{{Br_2}} (C)$
$(2)$ Ethane $\xrightarrow[{hv}]{{Cl_2}} (B)$ $\xrightarrow[{Na, \text{ether}}]{} (C)$

Which of the following statements is incorrect?

Given below are two statements:
Statement $I$: $3$-phenylpropene reacts with $HBr$ and gives secondary alkyl bromide having a chiral carbon atom as the major product.
Statement $II$: Aryl chlorides and aryl cyanides can be prepared by Sandmeyer reaction as well as Gattermann reaction.

The end product of the given reaction is:

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