How many isomers are possible for the formula | vedclass

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(A) The molecular formula $C_2BrClF_4$ represents a derivative of ethane where hydrogen atoms are replaced by halogens. To find the isomers,we conside

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$3$

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(A) The molecular formula $C_2BrClF_4$ represents a derivative of ethane where hydrogen atoms are replaced by halogens. To find the isomers,we consider the arrangement of atoms around the $C-C$ bond. For $C_2BrClF_4$,the possible structural isomers are based on the distribution of atoms on the two carbon atoms: $1$. $CF_3-CFBrCl$ (one isomer) $2$. $CF_2Cl-CF_2Br$ (one isomer) For $CF_3-CFBrCl$,the carbon atom attached to $Br$ and $Cl$ is chiral,leading to $2$ enantiomers ($d$ and $l$ forms). For $CF_2Cl-CF_2Br$,there are no chiral centers,but it can exhibit rotational isomerism (conformations),though typically in structural isomerism counting,we look for distinct connectivity. However,considering stereoisomerism: $CF_3-CFBrCl$ has $2$ enantiomers. $CF_2Cl-CF_2Br$ has no stereoisomers. Total isomers = $2$ (enantiomers) + $1$ (structural isomer) = $3$.

How many isomers are possible for the formula $C_2BrClF_4$?

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