Which of the following does not show geometri | vedclass

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Question

(B) Geometrical isomerism in cyclic compounds requires that at least two carbons in the ring have different groups attached to them.In structure $(1)$

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) Geometrical isomerism in cyclic compounds requires that at least two carbons in the ring have different groups attached to them.In structure $(1)$,the $1,2$-dichlorocyclopropane has two different groups on each of the two carbons,allowing for cis and trans forms.In structure $(2)$,the $1,1$-dichlorocyclopropane has two identical $Cl$ atoms on the same carbon atom,which prevents the existence of geometrical isomers.In structure $(3)$,the $1,2$-dibromo-$1,2$-dichlorocyclobutane has different groups on the carbons,allowing for geometrical isomerism.In structure $(4)$,the $1,2,3$-trimethylcyclohexane has different groups on the carbons,allowing for geometrical isomerism.Therefore,structure $(2)$ does not show geometrical isomerism.

Which of the following does not show geometrical isomerism?

Similar Questions

Explain geometric isomerism with an example.

Which of the following compound$(s)$ has '$Z$' configuration?

Which of the following compounds will show $cis-trans$ isomerism?
$(i)$ $(CH_3)_2C=CH-C_2H_5$
$(ii)$ $CH_2=CBr_2$
$(iii)$ $C_6H_5CH=CH-CH_3$
$(iv)$ $CH_3CH=CClCH_3$

Geometrical isomerism can be found in which of the following?

Draw $cis$ and $trans$ isomers of the following compounds. Also write their $IUPAC$ names:
$(i)$ $CHCl=CHCl$
$(ii)$ $C_{2}H_{5}C(CH_{3})=C(CH_{3})C_{2}H_{5}$

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