Which of the following carbanions is the most | vedclass

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(A) The stability of a carbanion is determined by the hybridization of the carbon atom bearing the negative charge. $1$. $HC \equiv C^{\ominus}$ has $

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$HC \equiv C^{\ominus}$

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(A) The stability of a carbanion is determined by the hybridization of the carbon atom bearing the negative charge. $1$. $HC \equiv C^{\ominus}$ has $sp$ hybridization ($50\% \ s$-character). $2$. $(CH_3)_2C = CH^{\ominus}$ has $sp^2$ hybridization ($33.3\% \ s$-character). $3$. $C_6H_5^{\ominus}$ has $sp^2$ hybridization ($33.3\% \ s$-character). $4$. $(CH_3)_3C - CH_2^{\ominus}$ has $sp^3$ hybridization ($25\% \ s$-character). Greater $s$-character increases the electronegativity of the carbon atom,making it better at holding the negative charge. Therefore,the $sp$ hybridized carbanion $HC \equiv C^{\ominus}$ is the most stable.

Column-$I$	Column-$II$
$A$. $CH_3-O^{+}=CH-CH_3$	$1$. Stable due to resonance
$B$. $F_3C^{+}$	$2$. Destabilised due to inductive effect
$C$. $(CH_3)_3C^{-}$	$3$. Stabilised by hyperconjugation
$D$. $CH_3-CH^{+}-CH_3$	$4$. $A$ secondary carbocation

Which of the following carbanions is the most stable?

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