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(C) The molecular mass of the hydrocarbon is $72 \ u$. The general formula for an alkane is $C_nH_{2n+2}$.$12n + 1(2n+2) = 72 \implies 14n = 70 \impli

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Neopentane

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(C) The molecular mass of the hydrocarbon is $72 \ u$. The general formula for an alkane is $C_nH_{2n+2}$.$12n + 1(2n+2) = 72 \implies 14n = 70 \implies n = 5$.Thus,the hydrocarbon is pentane $(C_5H_{12})$.The isomers of pentane are $n$-pentane,isopentane,and neopentane.Neopentane ($2,2$-dimethylpropane) has all $12$ hydrogen atoms equivalent.Therefore,upon reaction with a halogen,it produces only one mono-substituted alkyl halide.

Which isomer of a hydrocarbon with a molecular mass of $72 \ u$ gives only one mono-substituted alkyl halide upon reaction with halogen?

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