Arrange the following acids in decreasing ord | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The acidity of carboxylic acids depends on the stability of the conjugate base (carboxylate ion).Electron-withdrawing groups ($-I$ effect) stabili

Vedclass · Accepted Answer

$III > II > I$

Vedclass · Answer

(B) The acidity of carboxylic acids depends on the stability of the conjugate base (carboxylate ion).Electron-withdrawing groups ($-I$ effect) stabilize the conjugate base and increase acidity.The hybridization of the carbon atom attached to the carboxyl group determines the $-I$ effect strength: $sp > sp^2 > sp^3$.In $(III)$,the carbon is $sp$ hybridized (strongest $-I$ effect).In $(II)$,the carbon is $sp^2$ hybridized.In $(I)$,the carbon is $sp^3$ hybridized (weakest $-I$ effect).Therefore,the decreasing order of acidity is $III > II > I$.

Arrange the following acids in decreasing order of acidity:
$(I) CH_3CH_2COOH$
$(II) CH_2 = CH - COOH$
$(III) HC \equiv C - COOH$

Similar Questions

Which acid can be oxidised by Fehling solution?

Identify the product of the Fischer esterification reaction shown below:

Which is the strongest acid? ($pK_a$ value is given in the bracket)

Which of the following reduces Tollen's reagent?

Which among the following is $NOT$ a dicarboxylic acid?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Arrange the following acids in decreasing order of acidity:$(I) CH_3CH_2COOH$$(II) CH_2 = CH - COOH$$(III) HC \equiv C - COOH$