What is the total number of stereoisomers for | vedclass

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Question

(B) The structure of $2, 3-$dibromobutane is $CH_3-CH(Br)-CH(Br)-CH_3$.It contains $n = 2$ chiral centers.Since the molecule is symmetrical,the number

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) The structure of $2, 3-$dibromobutane is $CH_3-CH(Br)-CH(Br)-CH_3$.It contains $n = 2$ chiral centers.Since the molecule is symmetrical,the number of stereoisomers is calculated using the formula $2^{n-1} + 2^{(n/2)-1}$.Substituting $n = 2$: $2^{2-1} + 2^{(2/2)-1} = 2^1 + 2^0 = 2 + 1 = 3$.The three stereoisomers are: one pair of enantiomers ($d$ and $l$ forms) and one meso compound.

Column-$(I)$	Column-$(II)$
$(A)$ $C_2H_5-C(CH_3)(OH)-H$	$(p)$ $Cl-C(Br)(I)-H$
$(B)$ $Br-C(Cl)(I)-H$	$(q)$ $OH-C(CH_3)(C_2H_5)-H$
	$(r)$ $H_5C_2-C(OH)(CH_3)-H$
	$(s)$ $Cl-C(I)(Br)-H$

What is the total number of stereoisomers for $2, 3-$dibromobutane?

Similar Questions

Find the enantiomers of the structures in Column-$(I)$ from Column-$(II)$.
Column-$(I)$ Column-$(II)$
$(A)$ $C_2H_5-C(CH_3)(OH)-H$ $(p)$ $Cl-C(Br)(I)-H$
$(B)$ $Br-C(Cl)(I)-H$ $(q)$ $OH-C(CH_3)(C_2H_5)-H$
$(r)$ $H_5C_2-C(OH)(CH_3)-H$
$(s)$ $Cl-C(I)(Br)-H$

The absolute configuration of the compound is

Meso compounds do not show optical activity because

Which of the following can show optical activity?

Statement-$1$: Molecules that are not superimposable on their mirror images are chiral.
Statement-$2$: All chiral molecules have chiral centers.

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