What is the order of stability of 1^{circ}, 2 | vedclass

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(D) The stability of carbocations is primarily determined by the inductive effect and hyperconjugation. $3^{\circ}$ carbocations are the most stable d

Vedclass · Accepted Answer

$3^{\circ} > 2^{\circ} > 1^{\circ} > \overset{\oplus}{C}H_3$

Vedclass · Answer

(D) The stability of carbocations is primarily determined by the inductive effect and hyperconjugation. $3^{\circ}$ carbocations are the most stable due to the maximum number of alkyl groups providing electron density through the $+I$ effect and hyperconjugation. $2^{\circ}$ carbocations are less stable than $3^{\circ}$ but more stable than $1^{\circ}$. $1^{\circ}$ carbocations are less stable than $2^{\circ}$. $\overset{\oplus}{C}H_3$ (methyl carbocation) is the least stable as it lacks any alkyl groups to stabilize the positive charge. Therefore,the correct order of stability is $3^{\circ} > 2^{\circ} > 1^{\circ} > \overset{\oplus}{C}H_3$.

What is the order of stability of $1^{\circ}, 2^{\circ}, 3^{\circ},$ and $\overset{\oplus}{C}H_3$ carbocations?

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