How many meso isomers are possible for 2, 3, | vedclass

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(B) The structure of $2, 3, 4-	ext{pentanetriol}$ is $CH_3-CH(OH)-CH(OH)-CH(OH)-CH_3$.This molecule has $3$ chiral centers at $C_2, C_3,$ and $C_4$.T

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$2$

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(B) The structure of $2, 3, 4-	ext{pentanetriol}$ is $CH_3-CH(OH)-CH(OH)-CH(OH)-CH_3$.This molecule has $3$ chiral centers at $C_2, C_3,$ and $C_4$.The molecule is symmetric because the groups attached to $C_2$ and $C_4$ are identical ($-CH_3$ and $-OH$).For a symmetric molecule with $n$ chiral centers,the number of meso isomers is calculated as follows:If $n$ is odd,the number of meso isomers is $2^{(n-1)/2}$.Here,$n = 3$,so the number of meso isomers $= 2^{(3-1)/2} = 2^1 = 2$.The two meso isomers are the $(2R, 3s, 4S)$ and $(2S, 3s, 4R)$ configurations (where $s$ denotes the pseudo-asymmetric center).

How many meso isomers are possible for $2, 3, 4-\text{pentanetriol}$?

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