Which of the following underlined carbon atom | vedclass

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(D) To determine the hybridization of a carbon atom,we count the number of $\sigma$ bonds and lone pairs attached to it.$1$. $sp^3$ hybridization: Car

Vedclass · Accepted Answer

$CH_3CH_2\underline{C}N$

Vedclass · Answer

(D) To determine the hybridization of a carbon atom,we count the number of $\sigma$ bonds and lone pairs attached to it.$1$. $sp^3$ hybridization: Carbon is bonded to $4$ atoms (all single bonds,$4\sigma$ bonds).$2$. $sp^2$ hybridization: Carbon is bonded to $3$ atoms (one double bond,$3\sigma$ bonds).$3$. $sp$ hybridization: Carbon is bonded to $2$ atoms (one triple bond or two double bonds,$2\sigma$ bonds).In option $D$,the structure is $CH_3-CH_2-C \equiv N$. The underlined carbon atom is bonded to one nitrogen atom via a triple bond and to one carbon atom via a single bond. Thus,it has $2\sigma$ bonds and $0$ lone pairs,resulting in $sp$ hybridization.

Which of the following underlined carbon atoms possesses $sp$ hybridization?

Similar Questions

Number of $sp$ hybridised carbon atoms in the given compound $CH_2=CH-C\equiv C-CH_2-CN$ is:

The compounds containing $sp$-hybridised carbon atom are:
$(I)$ $H_3C-N(CH_3)-CHO$
$(II)$ Pyridine
$(III)$ $H_3C-CN$
$(IV)$ $H_2C=C=CH-CH_3$

The pair of electrons in the given carbanion,$CH_{3}C\equiv C^{-},$ is present in which of the following orbitals?

Select the response that correctly identifies the number of carbon atoms of each type of hybridization in the compound given below:
$H_2C=C=CH-CHO$
(Order: $sp^3 - sp^2 - sp$)

Which of the following starred carbon atoms is the most electronegative?

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