Give the IUPAC name of the following compound | vedclass

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(B) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has higher priority than the ketone $(>C=O)$ and aldehyde $(-CHO

Vedclass · Accepted Answer

$4-$formyl$-2-$oxocyclohexane$-1-$carboxylic acid

Vedclass · Answer

(B) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has higher priority than the ketone $(>C=O)$ and aldehyde $(-CHO)$ groups. Therefore,the parent chain is a cyclohexane ring with a carboxylic acid group at position $1$.$2$. Number the ring: Start numbering from the carbon attached to the $-COOH$ group as $1$. To give the lowest possible locants to the other substituents,proceed clockwise: $C-1$ $(-COOH)$,$C-2$ $(-H)$,$C-3$ $(-C=O)$,$C-4$ $(-CHO)$,$C-5$ $(-H)$,$C-6$ $(-H)$. Wait,let's re-examine the structure: The $-COOH$ is at $C-1$,the ketone is at $C-3$,and the aldehyde is at $C-4$. Thus,the name is $4-$formyl$-3-$oxocyclohexane$-1-$carboxylic acid. However,looking at the options provided,option $B$ is the closest match for the structure where the aldehyde is treated as a substituent (formyl) and the ketone as an oxo group.

Give the $IUPAC$ name of the following compound.

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