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(D) The dissociation constant $(K_a)$ is a measure of the acidity of a compound. Higher acidity corresponds to a higher $K_a$ value.$1$. $C_6H_5OH$ (P

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$CH_3NH_3^+ Cl^-$

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(D) The dissociation constant $(K_a)$ is a measure of the acidity of a compound. Higher acidity corresponds to a higher $K_a$ value.$1$. $C_6H_5OH$ (Phenol) is a weak acid $(pK_a \approx 10)$.$2$. $C_6H_5CH_2OH$ (Benzyl alcohol) is less acidic than phenol $(pK_a \approx 15)$.$3$. $CH_3C \equiv CH$ (Propyne) is a very weak acid $(pK_a \approx 25)$.$4$. $CH_3NH_3^+ Cl^-$ (Methylammonium chloride) acts as a conjugate acid of a weak base,making it significantly more acidic than the others ($pK_a \approx 10.6$ for the ammonium ion,but in aqueous solution,the salt provides $CH_3NH_3^+$,which is a stronger acid compared to the neutral organic molecules listed).Comparing the acidity,the methylammonium ion is the strongest acid among the given options,thus it has the highest dissociation constant.

Which of the following compounds has the highest value of dissociation constant $(K_a)$?

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