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(D) The molecular formula $C_4H_{10}O$ corresponds to alcohols and ethers. The structural isomers are as follows:Alcohols:$1$. $CH_3CH_2CH_2CH_2OH$ (B

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$7$

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(D) The molecular formula $C_4H_{10}O$ corresponds to alcohols and ethers. The structural isomers are as follows:Alcohols:$1$. $CH_3CH_2CH_2CH_2OH$ (Butan$-1-$ol)$2$. $CH_3CH_2CH(OH)CH_3$ (Butan$-2-$ol)$3$. $(CH_3)_2CHCH_2OH$ ($2$-Methylpropan$-1-$ol)$4$. $(CH_3)_3COH$ ($2$-Methylpropan$-2-$ol)Ethers:$5$. $CH_3OCH_2CH_2CH_3$ ($1$-Methoxypropane)$6$. $CH_3OCH(CH_3)_2$ ($2$-Methoxypropane)$7$. $CH_3CH_2OCH_2CH_3$ (Ethoxyethane)Total structural isomers = $4$ (alcohols) + $3$ (ethers) = $7$.

How many structural isomers are possible for $C_4H_{10}O$?

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