What is the correct order of increasing basic | vedclass

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(A) The basicity of a conjugate base is inversely proportional to the acidity of its corresponding acid.$1$. The corresponding acids are: $RCOOH$ (car

Vedclass · Accepted Answer

$RCOO^- < HC \equiv C^- < NH_2^- < R^-$

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(A) The basicity of a conjugate base is inversely proportional to the acidity of its corresponding acid.$1$. The corresponding acids are: $RCOOH$ (carboxylic acid),$HC \equiv CH$ (alkyne),$NH_3$ (ammonia),and $RH$ (alkane).$2$. The acidity order of these acids is: $RCOOH > HC \equiv CH > NH_3 > RH$.$3$. Therefore,the basicity order of their conjugate bases is the reverse: $RCOO^- $4$. Thus,the correct order is $RCOO^- < HC \equiv C^- < NH_2^- < R^-$.

What is the correct order of increasing basicity for the given conjugate bases $(R = CH_3)$?

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