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(A) The acidity of a compound depends on the stability of its conjugate base. The more stable the conjugate base,the stronger the acid.$(1)$ $CH_2=CH_

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$2 < 1 < 4 < 3$

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(A) The acidity of a compound depends on the stability of its conjugate base. The more stable the conjugate base,the stronger the acid.$(1)$ $CH_2=CH_2$ (ethene): $sp^2$ hybridized carbon,conjugate base is $CH_2=CH^-$,$pKa \approx 44$.$(2)$ $CH_3-CH_3$ (ethane): $sp^3$ hybridized carbon,conjugate base is $CH_3-CH_2^-$,$pKa \approx 50$.$(3)$ $HC \equiv CH$ (ethyne): $sp$ hybridized carbon,conjugate base is $HC \equiv C^-$,$pKa \approx 25$.$(4)$ $NH_3$ (ammonia): conjugate base is $NH_2^-$,$pKa \approx 38$.Comparing the $pKa$ values (lower $pKa$ means higher acidity): $50 (2) Therefore,the increasing order of acidity is $2 < 1 < 4 < 3$.

What is the increasing order of acidity for the following substances?
$(1)$ $CH_2=CH_2$
$(2)$ $CH_3-CH_3$
$(3)$ $HC \equiv CH$
$(4)$ $NH_3$

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What is the increasing order of acidity for the following substances?$(1)$ $CH_2=CH_2$$(2)$ $CH_3-CH_3$$(3)$ $HC \equiv CH$$(4)$ $NH_3$