Identify the pair of complexes that have the | vedclass

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(B) The magnetic moment (spin-only) is given by $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons. Two complexes have the same

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$[Cr(H_2O)_6]^{2+}, [Fe(H_2O)_6]^{2+}$

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(B) The magnetic moment (spin-only) is given by $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons. Two complexes have the same magnetic moment if they have the same number of unpaired electrons $(n)$.$1$. $[Cr(H_2O)_6]^{2+}$: $Cr^{2+}$ is $3d^4$. $H_2O$ is a weak field ligand,so $n = 4$.$2$. $[CoCl_4]^{2-}$: $Co^{2+}$ is $3d^7$. $Cl^-$ is a weak field ligand,so $n = 3$.$3$. $[Fe(H_2O)_6]^{2+}$: $Fe^{2+}$ is $3d^6$. $H_2O$ is a weak field ligand,so $n = 4$.$4$. $[Mn(H_2O)_6]^{2+}$: $Mn^{2+}$ is $3d^5$. $H_2O$ is a weak field ligand,so $n = 5$.Comparing the values of $n$:$[Cr(H_2O)_6]^{2+}$ has $n = 4$ and $[Fe(H_2O)_6]^{2+}$ has $n = 4$.Therefore,they have the same magnetic moment.

Identify the pair of complexes that have the same magnetic moment (spin-only value).

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