What is the ionization isomer of [Cr(H_2O)_4C | vedclass

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(B) Ionization isomers are formed when a counter ion in the coordination sphere exchanges its position with a ligand present inside the coordination s

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$[Cr(H_2O)_4Cl_2]NO_2$

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(B) Ionization isomers are formed when a counter ion in the coordination sphere exchanges its position with a ligand present inside the coordination sphere.In the complex $[Cr(H_2O)_4Cl(NO_2)]Cl$,the $Cl^-$ ion is outside the coordination sphere.By exchanging the $Cl^-$ ion outside with the $NO_2^-$ ligand inside,we get the isomer $[Cr(H_2O)_4Cl_2]NO_2$.

What is the ionization isomer of $[Cr(H_2O)_4Cl(NO_2)]Cl$?

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