In the coordination complex [E(en)_2(C_2O_4)] | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the complex $[E(en)_2(C_2O_4)]NO_2$,both $en$ (ethylenediamine) and $C_2O_4^{2-}$ (oxalate) are bidentate ligands.Coordination Number $= (2 	i

Vedclass · Accepted Answer

$6$ and $3$

Vedclass · Answer

(B) In the complex $[E(en)_2(C_2O_4)]NO_2$,both $en$ (ethylenediamine) and $C_2O_4^{2-}$ (oxalate) are bidentate ligands.Coordination Number $= (2 	imes 2) + (1 	imes 2) = 4 + 2 = 6$.To find the oxidation state $(x)$ of $E$:$x + 2(0) + (-2) + (-1) = 0$$x - 3 = 0$$x = +3$.Therefore,the coordination number is $6$ and the oxidation state is $3$.

In the coordination complex $[E(en)_2(C_2O_4)]NO_2$,the coordination number and oxidation state of $E$ are respectively:

Similar Questions

Which of the following will give $Fe^{3+}$ ions in solution?

Which of the following is an example of a hexadentate ligand?

The number of ions formed when cuprammonium sulphate is dissolved in water is

Identify the homoleptic complex from the following:

$A$ complex of platinum,ammonia,and chloride produces four ions per molecule in the solution. Which structure is consistent with this observation?

Vedclass Test Series

Exam Paper Generator

Online Exam Module