Which type of atomic orbitals hybridize to form a square planar complex?

  • A
    $s, p_x, p_y, d_{yz}$
  • B
    $s, p_x, p_y, d_{x^2-y^2}$
  • C
    $s, p_x, p_y, d_{z^2}$
  • D
    $s, p_x, p_y, d_{xy}$

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Similar Questions

When $Ag^{+}$ reacts with excess of sodium thiosulphate,the obtained species having charge and geometry respectively will be?

Match the following:
Column-$I$ Complex Column-$II$ Structure / Geometry / Property
$A$. $[Ni(CN)_4]^{2-}$ $I$. Tetrahedral / Paramagnetic
$B$. $[Ni(CO)_4]$ $II$. Tetrahedral / Diamagnetic
$C$. $[NiCl_4]^{2-}$ $III$. Square planar / Diamagnetic
The correct match is:

If $Ni^{2+}$ is replaced by $Pt^{2+}$ in the complex $[NiCl_2Br_2]^{2-}$,which of the following properties are expected to change?
$A.$ Geometry
$B.$ Geometrical isomerism
$C.$ Optical isomerism
$D.$ Magnetic properties

In which of the following configurations will there be the possibility of both paramagnetism and diamagnetism,depending on the nature of the ligands?

The complex ion $[Cu(NH_3)_4]^{2+}$ is:

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