The hexafluoroferrate(III) ion is an outer or | vedclass

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(B) The chemical formula for the hexafluoroferrate$(III)$ ion is $[FeF_6]^{3-}$.In this complex,the oxidation state of $Fe$ is $x + 6(-1) = -3$,so $x

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$5$

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(B) The chemical formula for the hexafluoroferrate$(III)$ ion is $[FeF_6]^{3-}$.In this complex,the oxidation state of $Fe$ is $x + 6(-1) = -3$,so $x = +3$.The electronic configuration of $Fe^{3+}$ is $[Ar] 3d^5$.Since $F^-$ is a weak field ligand,it forms an outer orbital complex ($sp^3d^2$ hybridization).In the $3d$ orbitals,the $5$ electrons remain unpaired according to Hund's rule.Therefore,the number of unpaired electrons is $5$.

The hexafluoroferrate$(III)$ ion is an outer orbital complex. The number of unpaired electrons in it is.....

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