Which of the following has the highest magnet | vedclass

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(A) To determine the magnetic moment,we calculate the number of unpaired electrons $(n)$ in each complex:$1$. In $[FeF_6]^{3-}$,$Fe$ is in $+3$ oxidat

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$[FeF_6]^{3-}$

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(A) To determine the magnetic moment,we calculate the number of unpaired electrons $(n)$ in each complex:$1$. In $[FeF_6]^{3-}$,$Fe$ is in $+3$ oxidation state $(3d^5)$. Since $F^-$ is a weak field ligand,electrons do not pair up. Thus,$n = 5$.$2$. In $[Co(NH_3)_6]^{3+}$,$Co$ is in $+3$ oxidation state $(3d^6)$. $NH_3$ is a strong field ligand,causing pairing. Thus,$n = 0$.$3$. In $[Fe(CN)_6]^{4-}$,$Fe$ is in $+2$ oxidation state $(3d^6)$. $CN^-$ is a strong field ligand,causing pairing. Thus,$n = 0$.$4$. In $[Mn(CN)_6]^{4-}$,$Mn$ is in $+2$ oxidation state $(3d^5)$. $CN^-$ is a strong field ligand,causing pairing. Thus,$n = 1$.Since magnetic moment $\mu = \sqrt{n(n+2)} \ BM$,the complex with the highest $n$ has the highest magnetic moment. Therefore,$[FeF_6]^{3-}$ has the highest magnetic moment.

Which of the following has the highest magnetic moment?

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