In the complex [Pt(en)_2]^{2+},the coordinati | vedclass

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(D) $1$. The ligand '$en$' stands for ethylenediamine $(NH_2CH_2CH_2NH_2)$,which is a bidentate ligand. $2$. The coordination number $(C.N)$ is calcul

Vedclass · Accepted Answer

$C.N = 4, O.N = +2$

Vedclass · Answer

(D) $1$. The ligand '$en$' stands for ethylenediamine $(NH_2CH_2CH_2NH_2)$,which is a bidentate ligand. $2$. The coordination number $(C.N)$ is calculated as: $(	ext{number of ligands}) 	imes (	ext{denticity}) = 2 	imes 2 = 4$. $3$. Let the oxidation state of $Pt$ be $x$. The charge on ethylenediamine is $0$. $4$. The equation for the complex is: $x + 2(0) = +2$,which gives $x = +2$. $5$. Therefore,the coordination number is $4$ and the oxidation state is $+2$.

In the complex $[Pt(en)_2]^{2+}$,the coordination number and oxidation state of the central metal ion are,respectively:

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